Genetic Pattern of a Simple Recessive Trait

Copyright 2001
Laila Gistedt, Sweden.
Telephone
+46 8 266401.
email: laila.gistedt@tinctura.se
Colleen M. O'Keefe, USA
Telephone
217-523-1657
email: cok13@fgi.net

 

This is the method used to determine the heritability of a simple recessive trait, which is a question of probability.  Probability is the chance that a given event will occur.  With simple recessive inheritance there are three possible genes which can produce six possible combinations of breeding.

Each individual has 2 alleles which make one gene and will receive one allele (50%) from the father and one allele (50%) from the mother.  Alleles can either be dominant usually indicated by a capital letter (A) or recessive usually indicated by small letter (a).  For instance the color black is dominant (A) over the color red which is a recessive color (a), so whenever the black allele is present in the gene controlling color, then the animal will be black in color.  Since the recessive trait is unknown or hidden it often produces unhealthy or undesirable traits.  Sometimes it also provides desirable traits, like the lovely red color in Welsh Springer Spaniels.  

The 2 alleles can produce the following 3 genetic combinations.

The offspring will have one of the following combinations with one allele from the father and the other from the mother:

Homozygous AA 

Free from illness and not carrier. Both parents have given the dominant allele A

Heterozygous Aa 

Free from symptoms but carrier. One parent has given the dominant allele A and the other the recessive allele a. Since A is dominant over a the offspring will  not show the trait for a.

Homozygous aa

Will show the recessive trait and pass it on to its offspring. Both parents either are homozygous for a or are a carrier (heterozygous) for a.

Each parent provides one of two possible alleles to the offspring and below is the probability that an offspring will inherit the two alleles depending on the status of the parents.

AA                   x         AA

parent

A

A

AA

AA

AA

AA

AA

AA

100% of the offspring will be free from the recessive trait and not carrier

AA                   x        Aa

parent

A

A

A

AA

AA

a

Aa

Aa

50% of the offspring will have AA  and are not carriers and 50% Aa and be a carrier. None of the offspring will show signs of the recessive trait.

AA                   x         aa

parent

A

A

a

Aa

Aa

a

Aa

Aa

100% of the offspring will be Aa and be a carrier of the recessive trait.  None of the offspring will show the signs of the recessive trait.

Aa                    x         Aa

parent

A

a

A

AA

Aa

a

Aa

aa

25% of the offspring will be AA and will not carriers. 50% will be Aa and will be carriers.  25% will be aa and will show signs of the recessive trait.

 

Aa                    x         aa

parent

A

a

a

Aa

aa

a

Aa

aa

50% of the offspring will be Aa and be carriers. 50% of the offspring will be aa and show the recessive trait.

aa                     x         aa

parent

a

a

a

aa

aa
a aa aa
100% of the offspring will show the recessive trait.